Resolvamos :
( 5/2)x + (2/3)x = (95/2)x^2
5x/2 + 2x/3 = (95x^2)/2
Saquemos el MCM de ( 2 y 3 ) = 6
[ (5x)*3] + [ (2x)*2] 95x^2
---------------------------------- = -----------------
6 2
15x + 4x 95x^2
----------------------- = ----------------------
6 2
19x = 6*( 95x^2)/2
19x = 3*(95x^2)
19x = 285x^2
0 = 285x^2 - 19x
Ordenemos la ecuación :
285x^2 - 19x = 0
Saquemos "Factor Común " :
19x * ( 15x - 1) = 0
19x = 0 15x - 1 = 0
x = 0/19 15x = 1
x = 0 x = 1/15
CS { 0 , 1/15 }
Espero te sriva , SaLuDos :)''
