(2x + 1)^2 = 3(x + 1)^2
Hay que desarrollar las potencias y preparar la ecuación
4x^2 + 4x + 1 = 3(x^2 + 2x + 1)
= 3x^2 + 6x + 3
4x^2 - 3x^2 + 4x - 6x + 1 - 3 = 0
x^2 - 2x - 2 = 0
Usando la fórmula general
delta = (-2)^2 - 4(1)(-2) = 12
raiz delta = 2(raiz de 3)
x = [- b +/- (raiz delta)]/2a
x = [2 - 2(razi de 3)]/2
= 1 - (raiz de 3) x1 = 1 - (raiz de 3)
x = 1 + (raiz de 3) x2 = 1 + (raiz de 3)
S = {[1 - (raiz de 3)], [1 + (raiz de 3)]}